Implement Dictionary Using Hashing Algorithms: C Program To

// Print the hash table void printHashTable(HashTable* hashTable) { for (int i = 0; i < HASH_TABLE_SIZE; i++) { Node* current = hashTable->buckets[i]; printf("Bucket %d: ", i); while (current != NULL) { printf("%s -> %s, ", current->key, current->value); current = current->next; } printf("\n"); } }

// Search for a value by its key char* search(HashTable* hashTable, char* key) { int index = hash(key); Node* current = hashTable->buckets[index]; while (current != NULL) { if (strcmp(current->key, key) == 0) { return current->value; } current = current->next; } return NULL; } c program to implement dictionary using hashing algorithms

// Create a new node Node* createNode(char* key, char* value) { Node* node = (Node*) malloc(sizeof(Node)); node->key = (char*) malloc(strlen(key) + 1); strcpy(node->key, key); node->value = (char*) malloc(strlen(value) + 1); strcpy(node->value, value); node->next = NULL; return node; } i++) { Node* current = hashTable-&gt

Here is the C code for the dictionary implementation using hashing algorithms: printf("Bucket %d: "

// Create a new hash table HashTable* createHashTable() { HashTable* hashTable = (HashTable*) malloc(sizeof(HashTable)); hashTable->buckets = (Node**) malloc(sizeof(Node*) * HASH_TABLE_SIZE); hashTable->size = HASH_TABLE_SIZE; for (int i = 0; i < HASH_TABLE_SIZE; i++) { hashTable->buckets[i] = NULL; } return hashTable; }

typedef struct HashTable { Node** buckets; int size; } HashTable;

int main() { HashTable* hashTable = createHashTable(); insert(hashTable, "apple", "fruit"); insert(hashTable, "banana", "fruit"); insert(hashTable, "carrot", "vegetable"); printHashTable(hashTable); char* value = search(hashTable, "banana"); printf("Value for key 'banana': %s\n", value); delete(hashTable, "apple"); printHashTable(hashTable); return 0; }