Alternatively, maybe the calculator is for the player to calculate how many balls they might need to aim for a Hole-in-One, based on probability.
Then, create a function that takes in all the necessary variables and returns the probability.
print(f"\nYour chance of a Hole-in-One is {chance:.2f}%") holeinonepangyacalculator 2021
Let me outline the code.
def main(): print("Pangya Hole-in-One Calculator 2021") distance = float(input("Enter distance to hole (yards): ")) club_power = float(input("Enter club power (yards): ")) wind_direction = input("Enter wind direction (headwind/tailwind/crosswind): ").lower() wind_strength = float(input("Enter wind strength (yards): ")) Alternatively, maybe the calculator is for the player
Hmm, I'm not exactly sure about the specific parameters required. The user didn't provide detailed info, but the name suggests it's for the game "Pangya" (which is a Korean golf game), calculating the chance of a Hole-in-One. So I need to think about how such a calculator would work in the context of the game.
Probability = (1 - abs((P + W) - D) / D) * A * S * 100 Probability = (1 - abs((P + W) -
accuracy = float(input("Enter player's accuracy stat (0-1): ")) skill_bonus = float(input("Enter skill bonus as a decimal (e.g., 0.15 for 15%): "))