Solution Manual Heat And Mass Transfer Cengel 5th Edition Chapter 3 Access

$\dot{Q}=\frac{T_{s}-T_{\infty}}{\frac{1}{2\pi kL}ln(\frac{r_{o}+t}{r_{o}})}$

Assuming $\varepsilon=1$ and $T_{sur}=293K$,

Assuming $k=50W/mK$ for the wire material, Assuming $k=50W/mK$ for the wire material

$Re_{D}=\frac{\rho V D}{\mu}=\frac{999.1 \times 3.5 \times 2}{1.138 \times 10^{-3}}=6.14 \times 10^{6}$

Solution:

$I=\sqrt{\frac{\dot{Q}}{R}}$

Solution:

$\dot{Q}=h \pi D L(T_{s}-T_{\infty})$