Worked Examples To Eurocode 2 Volume 2 Apr 2026
MEd = 1.35 x (2 x 4^2 / 8) + 1.5 x (1.5 x 4^2 / 8) = 18.9 kNm
The design shear force is:
λ = 3 / 0.4 = 7.5
MEd = 1.35 x (2 x 4^2 / 8) + 1.5 x (1.5 x 4^2 / 8) = 18.9 kNm
The design shear force is:
λ = 3 / 0.4 = 7.5